Wasn't this the problem? That the kernel was drawing too much voltage from the battery, or something like that I read.
As current goes up, resistance has to go down, so there will be a voltage drop across the battery terminals.
That's my understanding, someone correct me if I'm wrong, or otherwise help clear this up?
Many devices where there are two AA batteries (TV remotes, etc...) usually have the batteries wired in series. They need to do it to get the voltage high enough for some of the components.
Additionally, many batteries are actually made from multiple smaller batteries wired in series internally. For example, some 9V batteries are actually just 6 regular 1.5V batteries wired in series.
Of course, in these configurations, they generally discharge at a similar rate.
This being said anything short-circuiting the loop, can create a new pathway with less resistance (think molten metal, sparks etc). But modern batteries can send a lot more current then, magnifying the effect.
Can this happen in theory ?