Skip to content
Better HN
Top
New
Best
Ask
Show
Jobs
Search
⌘K
undefined | Better HN
0 points
sidko
8y ago
0 comments
Share
Bitcoin is NOT infinitely divisible. Each Bitcoin is divisible into 10^8. There were reasons to choose this number and isn't arbitrary [1].
[1]
https://bitcoin.stackexchange.com/questions/31933/why-is-bit...
0 comments
default
newest
oldest
wwwtyro
8y ago
It is arbitrarily divisible. Fitting inside 64 bits is convenient, but hardly an insurmountable engineering challenge. There's libraries that handle this sort of thing with ease.
j
/
k
navigate · click thread line to collapse