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0 pointsRusky6y ago0 comments

Yes, you're missing that the type `T&&` is a reference, not a value, and so does not run the object's destructor when it goes out of scope.

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dkersten6y ago

Sorry, I edited right after hitting reply to clarify that I'm assuming the intention was to std::move the unique_ptr in, since it was T&& and not T&. Would that still not work?

RuskyOP6y ago

It would still not work. All std::move does is cast to T&&, enabling overload resolution to pick a function with T&& as its parameter type.

dkersten6y ago

Thanks for explaining!

j / k navigate · click thread line to collapse

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dkersten6y ago

Sorry, I edited right after hitting reply to clarify that I'm assuming the intention was to std::move the unique_ptr in, since it was T&& and not T&. Would that still not work?

RuskyOP6y ago

It would still not work. All std::move does is cast to T&&, enabling overload resolution to pick a function with T&& as its parameter type.

dkersten6y ago

Thanks for explaining!

j / k navigate · click thread line to collapse