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0 pointsshasta15y ago0 comments

How do you figure? There isn't an implicit conversion from auto_ptr<T> to T *.

0 comments

There isn't. There are two explicit methods to get raw pointer value with different semantics:

- get(): auto_ptr retains the ownership

- release(): auto_ptr loses the ownership

j / k navigate · click thread line to collapse

There isn't. There are two explicit methods to get raw pointer value with different semantics:

- get(): auto_ptr retains the ownership

- release(): auto_ptr loses the ownership

j / k navigate · click thread line to collapse