undefined | Better HN

0 pointsTacticalCoder5y ago0 comments

> He didn't claim it is broken.

But then there's that line: "This destroys the RSA cryptosystem" in the abstract of the paper.

0 comments

Yes, because RSA 2048 is broken, not RSA 4096. Almost everything uses 2k, nobody uses 4k. The cryptosystem infrastructure would be broken. Not talking about the possible backdoors in the ECC NIST curves. Thanksfully we have the djb curves there.

j / k navigate · click thread line to collapse

0 pointsTacticalCoder5y ago0 comments

> He didn't claim it is broken.

But then there's that line: "This destroys the RSA cryptosystem" in the abstract of the paper.

0 comments

rurban5y ago

Yes, because RSA 2048 is broken, not RSA 4096. Almost everything uses 2k, nobody uses 4k. The cryptosystem infrastructure would be broken. Not talking about the possible backdoors in the ECC NIST curves. Thanksfully we have the djb curves there.

j / k navigate · click thread line to collapse