Okay, well your (wrong) semantic argument that "GMM violation = UB" is irrelevant, so I'll stop arguing against it other than hinting that there is not one single mention of the word "undefined" in the GMM spec. Back on topic: Go is not memory-safe. Your belief that "GMM violation = UB", where UB = memory corruption literally and by definition implies that Go is not memory-safe. Java (which is where the term "memory model" comes from) is memory-safe, C# is memory-safe. Go is not.
Dilettante programmers certainly do not know the following:
1. Go slices, strings, and interface values are unsafely non-atomic. It's documented on some obscure page (even the spec does not document it AFAIK, which is also broken).
2. What a data race is
Even if they know #1, they will still write code like: modifying a slice within a structure and setting a thread-shared pointer to point to that structure.
Again, most programmers are taught "things need locks, for reasons". At best, they will pointlessly lock things, then another programmer will come "debunk" them and remove the lock because "the thing being locked is atomic". Note how none of this involves any thought of the memory model. That's because they do not know it exists.
As for people who know #2, yes that is enough to avoid memory corruption without needing to know #1, however, they are not sufficiently informed how much data races matter (as executing shellcode is not an expected outcome of writes to your data being non observable).