undefined | Better HN

0 pointsWalterBright4y ago0 comments

> the compiler won't delete it and complain if bar is not defined

    extern void bar();

will define it to the satisfaction of the compiler. The linker won't complain if the compiler removes the call to it.

0 comments

And then you have the issue of not having types. consider this

  void my_bar_class_type::bar(my_bar_type<my_bar_type_2>::my_bar_inside_type paramater);

and you are calling something like

   myObject->bar(mySecondObject.getWhatever());

You have to mock up like everything

Or go up an abstraction layer so the type details are not needed.

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