A C-like parser will keep parsing an expression as long as it's legal. Take:
foo("bar") * a
It will parse the call to 'foo', then see the '*' which is an infix operator and parse the whole thing as a multiplication expression. In most C-like languages, '(' is both a prefix operator (for grouping) and an infix operator (for function calls). So:
foo("bar") (a + b)
Is ambiguous if you don't require semicolons to separate expressions. The parser will parse the call to foo, then see the '(' and parse that as a call to the value returned by 'foo'. To stop that, you use the semicolon to stop parsing one expression, so the next '(' is treated as a prefix operator.
