Skip to content
Better HN
Top
New
Best
Ask
Show
Jobs
Search
⌘K
undefined | Better HN
0 points
sedatk
2y ago
0 comments
Share
Haven't seen that, but how do you work with carry for numbers that are 256^8 < x < 58^11 ?
0 comments
default
newest
oldest
charlieyu1
2y ago
If we cut off at 8 byte blocks every number would be < 256^8. Encountering x > 256^8 would simplify be invalid.
sedatk
OP
2y ago
In that case, there would be padding left in every encoded block. The size overhead would weaken the case for Base58 especially if you consider using it for arbitrarily long data.
j
/
k
navigate · click thread line to collapse