The article's definition of not revealing information is a bit unclear, but if we understand it as Eve not knowing who holds any single card, your solution seems to work. At least assuming the following code is correct :)
import itertools
import functools
for eve_card in range(7):
cards_left = set(range(7))
cards_left.remove(eve_card)
mod_to_cards = [[], [], [], [], [], [], []]
for c in itertools.combinations(cards_left, 3):
mod = sum(c) % 7
mod_to_cards[mod].append(set(c))
for combs in mod_to_cards:
i = functools.reduce(lambda x, y: x.intersection(y), combs)
if len(i) != 0:
print("intersection", eve_card, combs, i)
u = functools.reduce(lambda x, y: x.union(y), combs)
if len(u) != 6:
print("union", eve_card, combs, u)
