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0 pointsacchow11mo ago0 comments

Correct. ZGC has no way to escape from the virtualization by the kernel (assuming your hardware and kernel uses an MMU)

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MBCook11mo ago

Thank you for the answer, I was wondering that as well.

j / k navigate · click thread line to collapse

0 pointsacchow11mo ago0 comments

Correct. ZGC has no way to escape from the virtualization by the kernel (assuming your hardware and kernel uses an MMU)

MBCook11mo ago

Thank you for the answer, I was wondering that as well.

j / k navigate · click thread line to collapse