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0 pointsamai7mo ago0 comments

What does Wildberger then think about i = sqrt(-1)? Is this also "not accurate" enough?

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Ultrafinitism does not rule out higher algebraic structures

j / k navigate · click thread line to collapse

0 pointsamai7mo ago0 comments

What does Wildberger then think about i = sqrt(-1)? Is this also "not accurate" enough?

Ultrafinitism does not rule out higher algebraic structures

j / k navigate · click thread line to collapse