The antiderivative of 1/x is ln(x), not ln |x (opens in new tab)

(blog.danielh.cc)

2 pointsmax__dev7mo ago2 comments

2 comments

Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i

1/x = ln|x| + C if x > 0

ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)

In reals ln|x| is fine.

j / k navigate · click thread line to collapse

Sir what you wrote down is equivalent to integral 1/x = ln|x| if x > 0 else ln|x| + pi*i

1/x = ln|x| + C if x > 0

ln|x| + pi*i + C or ln|x| - pi*i + C or is x < 0 (Protip: Choose C=-+pi*i)

In reals ln|x| is fine.

j / k navigate · click thread line to collapse