Skip to content
Better HN
Top
New
Best
Ask
Show
Jobs
Search
⌘K
0 points
pfortuny
8d ago
0 comments
Share
I know, yes, but did not want to digress. Thanks though. Actually, it is the "extension" to K[e] with e^2=0, as "usual".
undefined | Better HN
0 comments
default
newest
oldest
measurablefunc
8d ago
The infinitesimally thickened point.
j
/
k
navigate · click thread line to collapse