undefined | Better HN

0 pointsfrozenport13y ago0 comments

The imaginary part of the transform.

0 comments

The article uses the magnitude of the coefficients, which is computed using both the real and the imaginary part.

The phase portion isn't actually just the imaginary part, it's just the piece of information lost when one goes from real+imag -> magnitude, i.e. it's the argument of the complex number.

j / k navigate · click thread line to collapse

0 pointsfrozenport13y ago0 comments

The imaginary part of the transform.

0 comments

nphrk13y ago

The article uses the magnitude of the coefficients, which is computed using both the real and the imaginary part.

dbaupp13y ago

The phase portion isn't actually just the imaginary part, it's just the piece of information lost when one goes from real+imag -> magnitude, i.e. it's the argument of the complex number.

j / k navigate · click thread line to collapse