Lazy Ruby (opens in new tab)

I think I would write the fibs expression as

    fibs = [true,false].lazy.flat_map{|i| if i then [1,1] else fibs.zip(fibs.drop(1)).map{|a,b| a+b} end}

instead of the author's

    fibs = inf.map do |n|
        if n < 3
          1
        else
          fibs.zip(fibs.drop(1)).map { |a, b| a + b }.first(n - 2).last
        end
      end

because I think my way looks a lot closer to the Haskell version. It still has the problem that Enumerator::Lazy doesn't memoize, so finding the nth element of fibs (in either of these two Ruby versions) does an exponential (Fibonacci, in fact) number of additions, unlike the Haskell version that does n-1 additions.

I would memoize with an alias_method wrapper and let it hit a cache_hash before calling the original function. This is a generic pattern that should work for all immutable functions.

http://stackoverflow.com/questions/21790868/simple-aspect-or...

I once contrived a Y-Combinator-backed and memoized implementation of fib() in pure C (with the blocks extension for real closures). It was a mess, but it was pretty cool:

http://kswizz.com/post/50429268286/fibonacci-the-y-combinato...

On a similar theme, I did a blog post a while back on lazy quicksort in Ruby: http://mossity.com/2013/08/17/implementing-a-lazy-quicksort-...

I wrote the following blog post a while back on a similar note. ;)

http://jasdeep.ca/2012/08/easy-memoization-ruby/