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0 pointscomex11y ago0 comments

Not quite - what matters (normally) is the address of the symbol, not the bytes located there, since in the case of a real function those bytes would be the instructions. So this will either execute the bytes at &main as instructions (4 zero bytes, and whatever follows), or, more likely, crash due to memory protections, as described in the article.

0 comments

zwegner11y ago

Yup. You can get a working program with the simple:

  const int main = 0xC3;

...which is just a return. Or you can get fancy and make it exit successfully by clearing eax first:

  const int main = 0xC3C031;

j / k navigate · click thread line to collapse

0 pointscomex11y ago0 comments

0 comments

zwegner11y ago

Yup. You can get a working program with the simple:

  const int main = 0xC3;

...which is just a return. Or you can get fancy and make it exit successfully by clearing eax first:

  const int main = 0xC3C031;

j / k navigate · click thread line to collapse