01GOD

First, to any new to the topic:

1. According to "W.H.O/china joint mission final report", "Alignment of the full-length genome sequence of the COVID-19 virus and other available genomes of Betacoronavirus showed the closest relationship was with the bat SARS-like coronavirus strain BatCov RaTG13, identity 96%"

2. That genome sequence happens to be a genome sequence submitted to NCBI by "Wuhan Institute of Virology", a lab located about 14km walking distance from the supposed epicenter of a global epidemic!!!

Here is the link to that report (that china was apparently involved with the W.H.O. in making): https://www.who.int/docs/default-source/coronaviruse/who-china-joint-mission-on-covid-19-final-report.pdf

And here is the BatCov RaTG13" sequence with that lab's name on it: https://www.ncbi.nlm.nih.gov/nuccore/MN996532

NOTE: BOTH of those documents are basically data from chinese sources, NOT any third party, aside from W.H.O. (and NCBI hosting a document submitted by the chinese lab).

OBVIOUSLY the chinese government hasn't seemed so forthcoming about that lab and has seemingly been trying desperately to push it under the proverbial rug so most of the human species won't know where covid19 leaked from.

Some in the scientific community (Ebright at Rutgers, for instance) have started to expose the safety concerns of wuhan labs and MORE SHOULD BE DOING SO!!! Calling on the scientific community to rally to motivate transparency and also IMPORTANTLY to force the bio-research community to put the safety of the World above bio-research funding of such labs!!!

Thanks in advance to all that do!!!

So basically it is f(f(f(do stuff here or put value here or both))) with more parenthesis as it runs or is it f(((do stuff here or put values here or both))) with more parenthesis as it runs? Basically looks like this f(((((((λx. f (x x)) (λx. f (x x)))))))) with growing numbers of parenthesis or are there f's between the left parenthesis? Currently believe it is likely f(f(f(f and so on...AKA: "function with same function as input here: (function with same function as input here: (function with same function as input here:" and so on. Thanks in advance for confirming and clarifying. PS: Can confirm how the y combinator gets past step 3 in the following list of iterations? IE: Does the input function get passed in as f again somehow or is the f on left side of the function always automatically assigned the original input value on every pass?: Step 1: (λf. (λx. f (x x))(λx. f (x x)))SomeFunction Step 2: (λx. SomeFunction (x x))(λx. f (x x)) Step 3: SomeFunction(λx. f (x x))(λx. f (x x)) Step 4 (Want to make sure this "f is automatically assigned SomeFunction as val on every pass" step is correct): SomeFunction(SomeFunction(λx. f (x x))(λx. f (x x)))

So basically it is f(f(f(do stuff here or put value here or both))) with more parenthesis as it runs or is it f(((do stuff here or put values here or both))) with more parenthesis as it runs? Basically looks like this f(((((((λx. f (x x)) (λx. f (x x)))))))) with growing numbers of parenthesis or are there f's between the left parenthesis? Currently believe it is likely f(f(f(f and so on...AKA: "function with same function as input here: (function with same function as input here: (function with same function as input here:" and so on. Thanks in advance for confirming and clarifying.

PS: Can confirm how the y combinator gets past step 3 in the following list of iterations? IE: Does the input function get passed in as f again somehow or is the f on left side of the function always automatically assigned the original input value on every pass?: Step 1: (λf. (λx. f (x x))(λx. f (x x)))SomeFunction Step 2: (λx. SomeFunction (x x))(λx. f (x x)) Step 3: SomeFunction(λx. f (x x))(λx. f (x x)) Step 4 (Want to make sure this "f is automatically assigned SomeFunction as val on every pass" step is correct): SomeFunction(SomeFunction(λx. f (x x))(λx. f (x x)))